For the first-order rate of reaction A --> B + C, what is the concentration of A (in M) after 46.0 s if [A]_{o} = 0.40 M and k = 0.050 s^{-1}?

Here we are told that the reaction rate is first order.

Use the first order integrated rate equation (can also be found on your ACS periodic table) and the given values to find [A].

For a first-order reaction, the initial reactant concentration is 0.789 M. After 64.7 min, the concentration is 0.520 M. What is k in min^{-1}?

Use first order integrated rate equation and given values to solve for k.

For a first order reaction, the initial reactant concentration, [A]_{o}, is 0.94 M. After 14.4 s, the concentration is 0.67 M. What is [A] after 82 s?

Hint given in feedback

Hint given in feedback

Do the problem in 2 steps. First find k and then the new concentration. Both steps are done using first order integrated rate equation.

Step 1:

Step 2:

Suppose the rate of reaction is second order for A → B + C.

What is the concentration of A (in M) after 93.0 s if [A]_{o} = 0.70 M and k = 0.034 M^{-1}s^{-1}

Help: Second order rate of reaction

Use the second order integrated rate equation (can also be found on your ACS periodic table) and the given values to find [A].

For a second-order reaction, the initial reactant concentration is 0.90 M. After 14.8 min, the concentration is 0.28 M. What is k in M^{-1}min^{-1}?

Help: Second order rate of reaction and k

Use second order integrated rate equation and given values to solve for k.

For a second order reaction, the initial reactant concentration, [A]_{o}, is 0.94 M. After 11.7 s, the concentration is 0.59 M. What is [A] after 80 s?

Hint given in feedback

Hint given in feedback

Solve the problem in 2 steps. First fine k (like earlier problems) and then use the second order integrated rate equation to get the concentration.

Step 1:

Step 2:

For the zero-order rate of reaction A → B + C, what is the concentration of A (in M) after 36.0 s if [A]_{o} = 0.80 M and k = 0.010 Ms^{-1}?

Use zero order integrated rate equation and given values to solve for [A].

For a certain reaction, when the natural log of the reactant concentration is plotted against the time in seconds a straight line is obtained. What is the reaction order?

Select one:

Concise explanation and comparison of orders and plots can be found here.

It will serve you well to remember which graphs are linear for which orders, as this topic is likely to be on the final exam, not to mention your upcoming common exam! ;) .

*Zero order: linear for [A] v. time*

*First order: linear for ln[A] v. time*

*Second order: linear for 1/[A] v. time*

For the above reaction, the slope is -0.016. What are the units of the slope and what is k? Note, logs are unitless! Additional hint given in feedback.

Select one or more:

The slope is the change in y divided by the change in x. So, the units are the units of y divided by the units of x.

This example plot may help you understand why k is positive

For the reaction D → A + C when 1/[D] is plotted versus the time in seconds, a straight line is obtained whose slope is 0.017 M^{-1}s^{-1}. What is the concentration of D (in M) after 95.0 s if [D]_{o} = 0.80 M? Hint given in feedback

First use the information given about the plot to determine the order of the reaction and k.

*Zero order: linear for [A] v. time*

*First order: linear for ln[A] v. time*

*Second order: linear for 1/[A] v. time*

The fact that the plot is linear for 1/[D] v. time tells us that we have a second order reaction.

Next use appropriate integrated rate equation to determine the concentration:

For the reaction A → B + C when [A] is plotted versus the time in minutes a straight line is obtained whose slope is -0.011 M/min. What is the concentration of A (in M) after 10.00 min if [A]_{o} = 0.70 M?

Same as above.

For the reaction A → B + C, when the natural log of [A] is plotted versus the time in seconds a straight line is obtained whose slope is -0.042 s^{-1}. What is the concentration of A (in M) after 49.0 s if [A]_{o} = 0.90 M?

Same as above.

Imagine yourself as the goalie, and the professor as the offender.

Don't let him/her get one bit of knowledge or info past you during lecture without you understanding it!

Ask questions, read ahead of time–do whatever it takes to prevent him/her from "scoring."

This is perspective can definitely make lecture and learning more fun and easy.