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Question 1

Consider the balanced equation:

5A + 5B ↔ 7C + 5D

How many moles of B are required to produce 5 moles of D? Explanation

RATIOS

5B:5D

aka for every 5Bs used 5Ds are created

so 5Bs are need to create 5Ds

Question 2

Consider the new balanced equation:

3A + 7B ↔ 5C + 4D

How many moles of D are produced when 5 moles of C are produced? Explanation

Whenever 5Cs are created, 4 Ds are created as well as a reaction will always go fully (ratio wise)!

Question 3

Consider the balanced equation:

5A + 7B ↔ 7C + 6D

How many moles of B are required to produce 6 moles of D? Explanation

7B:6D

7 moles of B create 6 moles of D!

Pretty friggin' lit if I do say so myself!

Question 4

Consider the balanced equation:

6A + 2B ↔ 8C + 2D

How many moles of C can be produced from 8 moles of B? 2B:8C

2*4=8

8*4=32

8B:32C

Question 5

Consider the new balanced equation:

7A + 3B ↔ 6C + 2D

How many moles of A are required to react with 8 moles of B? Explanation

7A:3B

3X=8

X=8/3

7*(8/3)= 56/3=18.66

Question 6

Consider the balanced equation:

6A + 2B ↔ 7C + 2D

How many moles of C can be produced from 0.16 moles of B? 2B:7C

2X=.16

X=(2/25)

7*(2/25)=14/25

Question 7

Consider the new balanced equation:

5A + 2B ↔ 5C + 3D

How many moles of A are required to react with 0.76 moles of B? 5A:2B

2X=.76

5*(.76/2)=1.9

Question 8

Consider the balanced equation:

2A + 5B ↔ 3C + D

8 mol A are mixed with 15 mol B at an elevated temperature. After 4 mol of A have reacted, how much B is left? Explanation

2A:5B

8A:20B

6A:15B (B is the limiting reagent)

4A:10B

15B-10B= 5B

Question 9

Consider the balanced equation:

2A + 5B ↔ 3C + D

0.37 mol A are mixed with 1.16 mol B at an elevated temperature. After 0.05 mol of A are left, how much B is left? Hint given in feedback. Explanation

Hint, find out how much A reacted, then proceed as in the previous problem.

2A : 5B

.37A : .925B (A is the limiting reagent)

.464 : 1.16B

..37-.05=.32

.32A:.8B

1.16-.8=.36

Question 10

Consider the balanced equation:

2A + 5B ↔ 3C + D

0.37 mol A are mixed with 1.15 mol B at an elevated temperature. After 0.05 mol of A are left, how much C is produced? Explanation

Use the steps above kiddos I believe in ya alright truly this is only the beginning!

2A:5B:3C

.37A:.925B:.555C

.32A:.80B:.48C