## CHAPTER 3 BASIC HOMEWORK II

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* Answer Explanations Coming Soon! *

**Question 1**

Consider the balanced equation: 5A + 5B ↔ 7C + 5D How many moles of B are required to produce 5 moles of D?

**Explanation**

**Explanation**

RATIOS 5B:5D aka for every 5Bs used 5Ds are created so 5Bs are need to create 5Ds

**Question 2**

Consider the new balanced equation: 3A + 7B ↔ 5C + 4D How many moles of D are produced when 5 moles of C are produced?

**Explanation**

**Explanation**

Whenever 5Cs are created, 4 Ds are created as well as a reaction will always go fully (ratio wise)!

**Question 3**

Consider the balanced equation: 5A + 7B ↔ 7C + 6D How many moles of B are required to produce 6 moles of D?

**Explanation**

**Explanation**

7B:6D 7 moles of B create 6 moles of D! Pretty friggin’ lit if I do say so myself!

**Question 4**

Consider the balanced equation: 6A + 2B ↔ 8C + 2D How many moles of C can be produced from 8 moles of B? Help: Using balanced equations

**Explanation**

**Explanation**

2B:8C 2*4=8 8*4=32 8B:32C

**Question 5**

Consider the new balanced equation: 7A + 3B ↔ 6C + 2D How many moles of A are required to react with 8 moles of B?

**Explanation**

**Explanation**

7A:3B 3X=8 X=8/3 7*(8/3)= 56/3=18.66

**Question 6**

Consider the balanced equation: 6A + 2B ↔ 7C + 2D How many moles of C can be produced from 0.16 moles of B? Help: Using balanced equations (review)

**Explanation**

**Explanation**

2B:7C 2X=.16 X=(2/25) 7*(2/25)=14/25

**Question 7**

Consider the new balanced equation: 5A + 2B ↔ 5C + 3D How many moles of A are required to react with 0.76 moles of B?

**Explanation**

**Explanation**

5A:2B 2X=.76 5*(.76/2)=1.9

**Question 8**

Consider the balanced equation: 2A + 5B ↔ 3C + D 8 mol A are mixed with 15 mol B at an elevated temperature. After 4 mol of A have reacted, how much B is left? Help: Balanced equation yield

**Explanation**

**Explanation**

2A:5B 8A:20B 6A:15B (B is the limiting reagent) 4A:10B 15B-10B= 5B

**Question 9**

Consider the balanced equation: 2A + 5B ↔ 3C + D 0.37 mol A are mixed with 1.16 mol B at an elevated temperature. After 0.05 mol of A are left, how much B is left? Hint given in feedback.

**Explanation**

**Explanation**

Hint, find out how much A reacted, then proceed as in the previous problem.

2A : 5B

.37A : .925B (A is the limiting reagent)

.464 : 1.16B

..37-.05=.32

.32A:.8B

1.16-.8=.36

**Question 10**

Consider the balanced equation: 2A + 5B ↔ 3C + D 0.37 mol A are mixed with 1.15 mol B at an elevated temperature. After 0.05 mol of A are left, how much C is produced?

**Explanation**

**Explanation**

Use the steps above kiddos I believe in ya alright truly this is only the beginning! 2A:5B:3C .37A:.925B:.555C .32A:.80B:.48C