CHEM125 – CHAPTER 05 – BASIC HOMEWORK I

CHAPTER 5 BASIC HOMEWORK

Resources:

Have you found videos, websites, or explanations that helped you understand this chapter? Let us know and we’ll add them to “Resources” part of this page for other students to use.

Question 1

What is the pressure in atm of 383 mmHg? Help: Pressure–gases Answer:

Explanation

1 atm = 760 mmHg 1/ 760 = X/ 383 X= 0.5039

Question 2

What is the pressure in torr of 1.47 atm? Answer:

Explanation

760 torr = 1 atm 760 /1 = X / 1.47 X= 1117.2

Question 3

What is the pressure in atm of a gas where n = 0.16 mol, V = 13.76 L, and T = 28.4oC? Help: Ideal gas law Answer:

Explanation

PV=nRT 28.4oC= 301.55 K R=0.08206 P(13.76) = (0.16)(0.08206)(301.55) P=0.2877

Question 4

What is the temperature in K of an ideal gas where P = 728 torr, n = 0.0271 mol, and V = 476.5 mL? Hint for finding T using PV = nRT Answer:

Explanation

PV=nRT (728/760)(.4765)=(0.0271)(0.08206)T =205.24

Question 5

How many moles of an ideal gas produce a pressure of 744 torr and a volume of 2.30 L at 285 K? Answer:

Explanation

PV=nRT (744/760)(2.30L) = n (0.08206)(285) n=0.0962744

Question 6

If the mass of the gas in the preceding problem is 33.1 g, what is the molar mass or molecular weight of the gas? Help: Molecular weight Answer:

Explanation

33.1 g / X MM = 0.0962744 X= 343.81

Question 7

At a fixed temperature and number of moles, the initial volume and pressure of a helium gas sample are 238 mL and 685 torr, respectively. What is the final volume in mL, if the final pressure is 66.3 torr? Help: Boyle’s Law Answer:

Explanation

P1V1 = P2V2 238(685) = 66.3 X X=2458.974

Question 8

At a fixed temperature and number of moles of nitrogen gas, its volume and pressure are 196 mL and 687 torr, respectively. What is the final pressure in torr, if the final volume is 290 mL? Answer:

Explanation

196(687)= 290 X X=464.317

Question 9

At a fixed pressure and number of moles, the initial volume and temperature of an air sample are 491 mL and 270 K, respectively. What is the final volume in mL, if the final temperature is 481 K? Help: Charles Law Answer:

Explanation

V1/T1 = V2/T2 491/270 = X/481 874.707407

Question 10

To what temperature in K must a variable volume container of helium gas be cooled to obtain a final volume of 0.255 L? The initial volume and temperature are 2.86 L and 332 K, respectively. The pressure and number of moles are fixed. Answer:

Explanation

2.86/332 = 0.255 / X X=29.601

Question 11

A balloon filled with air and having no leak initially has a volume of 27.5 L, a pressure of 732 torr, and a temperature of 287 K. What is the final volume in L, if the final pressure is 489 torr and the final temperature is 244 K? Help: Ideal gas law, n fixed Answer:

Explanation

P1V1/T1 = P2V2/T2 (732)(27.5)/287 = (489)T/244 T=34.997

Question 12

What is the total pressure if a container contains 59 torr of He gas, 234 torr of N2 gas, and 44 torr of Ar gas? Help: Dalton’s Law Answer:

Explanation

59 + 234 + 44 = 337

Question 13

Oxygen gas is collected over water. The total pressure (the O2 pressure + the water vapor pressure) is 735 torr. The temperature of the water is such that the water vapor pressure is 44 torr. What is the partial pressure of the oxygen gas in torr? Answer:

Explanation

735 – 44 = 691

Question 14

What volume in L of chlorine at 30oC and 702 torr is required to react completely with 4.48 g aluminum: 2Al(s) + 3Cl2(g) → 2AlCl3(s) Hint for chlorine Answer:

Explanation

Procedure: g Al –> mol Al –> mol Cl2. Next solve for V in PV = nRT. Did you remember to convert torr to atm and C to K?   4.48 g Al / 26.981 MM = 0.166 mol Al 0.166 mol Al * 3 mol Cl2/ 2 mol Al = 0.24906 mol Cl2   PV= nRT (702/760)V= (0.24906)(0.08206)(303.15) V = 6.54