CHAPTER 14 REGULAR HOMEWORK:
EQUILIBRIUM I
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Question 1
For the reaction: 2H2O(g) ↔ 2H2(g) + O2(g)
What are the correct values of x, y, and z for the equilibrium expression to be correct?
Select one or more:
Explanation
Question 2
For the reaction: CO(g) + Cl2(g) ↔ COCl2(g)
What are the correct values of x, y, and z for the equilibrium expression to be correct?
Explanation
Question 3
For the reaction: CO2(g) ↔ CO(g) + 0.5O2(g)
What are the correct values of x, y, and z for the equilibrium expression to be correct?
Question 4
For the reaction: Si(s) + O2(g) ↔ SiO2(s)
What are the correct values of x, y, and z for the equilibrium expression to be correct?
Question 5
At a certain temperature the equilbrium constant is 135 for
H2(g) + I2(g) ↔ 2HI(g)
Calculate the the equilbrium constant for
0.5H2(g) + 0.5I2(g) ↔ HI(g)
Question 6
The equilbrium constant for the water-gas shift reaction is 5.0 at 400 oC:CO(g) + H2O(g) ↔ CO2(g) + H2(g)
Determine Qc if the following amounts (in moles) of each component is placed in a 1.0 L container.
CO 0.53
H2O 0.27
CO2 0.89
H2 0.65
Explanation
Keq= 5
Q= [CO2][H2]/[CO][H20]
Q=[0.89][0.65]/[0.53][0.27]= 4.04
Question 7
Explanation
Q<Keq
goes to right
Question 8
Determine Qc if the following amounts (in moles) of each component is placed in a 1.0 L container.
CO 0.34
H2O 0.11
CO2 0.88
H2 0.80
Explanation
Q = [.88][.8]/[.11][.34]
=18.82
Question 9
Explanation
Q>Keq
goes to the left
Question 10
The equilbrium constant for the following reaction is 0.16 M0.5 at 3000 K:
CO2(g) ↔ CO(g) + 0.5O2(g)
Determine Qc if the following amounts (in moles) of each component is placed in a 3.00 L container.
CO2 0.900
CO 0.840
O2 0.200
Give answer to 3 decimal places.
Explanation
Remember to use concentration (mol/L)!!
Q= [O2]^.5[CO]/[CO2]
Q= (0.2/3)^.5(0.840/3)/(.900/3)
Q=.242
Question 11
Explanation
Q> K
goes to the left
Question 12
Determine Qc if the following amounts (in moles) of each component is placed in a 10.00 L container.
CO2 0.560
CO 0.260
O2 0.560
Explanation
Q= [O2]^.5[CO]/[CO2]
Q= [.560/10]^.5[.260/10]/[.560/10]
Q=.11
Question 13
Explanation
Q<Keq
goes to the right
Question 14
Phosgene is formed from carbon monoxide and chlorine. At 607 oC, Kc is approximately 13.5 M-1 or L/mol. Calculate Kp (in atm-1) at this temperature.
CO(g) + Cl2(g) ↔ COCl2(g)
Explanation
Kp = Kc (RT)^deltan
Kp= 13.5 (0.0821*(607-273.15)^1
Kp= .187
Question 15
Some ammonia is sealed in a container and allowed to equilibrate at a particular temperature. The reaction is endothermic.
2NH3(g) ↔ N2(g) + 3H2(g)
In which direction will the reaction occur if some ammonia is removed from the system?
Question 16
Question 17
Question 18
Question 19
Question 20
Chemists studied the formation of phosgene by sealing 0.76 atm of carbon monoxide and 1.14 atm of chlorine in a reactor at a certain temperature. The pressure dropped smoothly to 1.32 atm as the system reached equilbrium. Calculate Kp (in atm-1) for
CO(g) + Cl2(g) ↔ COCl2(g)
Explanation
Hint, find the final pressure of each gas.
Use ICE Tables to solve:
CO Cl2 COCl2
I 0.76 1.14 0
C -x -x +x
E 0.76-x 1.14 -x x
1.32 = (0.76-x)+ (1.14-x)+x
Solve: -x=-0.58
x=0.58
CO Cl2 COCl2
I 0.76 1.14 0
C -0.58 -0.58 0.58
E 0.18 0.56 0.58
([0.58]/[0.18][0.56]) = 5.75
Question 21
Consider 1.80 mol of carbon monoxide and 3.80 mol of chlorine sealed in a 4.00 L container at 476 oC. The equilibrium constant, Kc, is 2.50 for
CO(g) + Cl2(g) ↔ COCl2(g)
Calculate the equilibrium molar concentration of CO.
Explanation
Hint, you need to find the equilibrium concentrations of all the gases. Note, that only one of the solutions to the quadratic equation makes sense (the other gives at least one negative concentration).
CO(g) + Cl2(g) ↔ COCl2(g)
I 1.8/4 3.8/4 0
C -x -x +x
E 1.8/4 -x 3.8/4 -x x
Kc = 2.5 = x/ (1.8/4 -x)(3.8/4-x)
x=.2815
1.8/4 – .2815 = .1685